APTITUDE & INTERVIEW

 Wipro Aptitude Questions with Solutions 1.The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is: A) 1 B) 2 C) 3 D) 4 Answer: B) 2 Explanation: Let the numbers 13a and 13b. Then, 13a x 13b = 2028 =>ab = 12. Now, the co-primes with product 12 are (1, 12) and (3, 4). [Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ] So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4). Clearly, there are 2 such pairs. 2.The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is: A) 123 B) 127 C) 235 D) 305 Answer: B) 127 Explanation: Required number = H.C.F. of (1657 – 6) and (2037 – 5) = H.C.F. of 1651 and 2032 = 127. 3.Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is: A) 40 B) 80 C) 120 D) 200 Answer: A) 40 Explanation: Let the numbers be 3x, 4x and 5x.

The ratio of boys to girls in a class in 7 to 3. Among the options below, an acceptable value for the total number of students in the class is: 21 37 50 73 ans: 50 A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits $8,000 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is: * $600 $605 $16,600 $16.605 Ans: $605 Let the representation of a number in base 3 be 210. What is the hexadecimal representation of the number? 15 21 D2 528 Ans: Firstly convert base 3 into a decimal number system(Base 10): (210)3=(x)10⟹0∗30+1∗31+2∗32=(21)10 Now convert (21)10 into a hexadecimal system. dividing by 16 that is: (21)10=(z)16                ∴z=(15)16           Option A is correct.   If the number 458X4 is divisible by 9, find the value of the digit marked as X. 4 5 6 7 Ans: 6 There are 8 batteries, but only 4 of them work. You have to use them for a flashlight which needs only 2 working batteries

IMPORTANTS ARE: Goldman Sachs important Questions 01 02 03 04 05 06 07 08 09 10 11 12 18 19 30 35 36 37 38 39 40 41 42 43 44 45 49* 50 51 52 53 54 55 56 57 58 59 60 61 62 75 77 78 79 80 85 92 95 96 100 103 115 116 117 118 119 120    1. At what percentage above the cost price must an article be marked, so as to gain 33% after allowing the customer a discount of 5%? A. 33% B. 45% C. 40% D. 51% Answer: Option C Explanation: Let us assume the C.P of the article as Rs. 100 It is mentioned that the gain is 33% So, S.P = 100 + 33%(C.P) = 100 + 33 = Rs. 133 This is the S.P after allowing 5% discount. 100% (M.P) - 5%(M.P) = S.P 95%(M.P) = 133 M.P = 133/0.95 M.P = 140 Therefore, Mark up % = [(M.P - C.P)/C.P] * 100 = [(140 - 100)/100] * 100 = 40% 2. How many three-digit numbers which are divisible by 7 can be formed using the first three prime numbers (without repetition)? A. 1 B. 2 C. 4 D. 6 Answer: Option Explanation: The first three prime numbers are 2, 3, and 5. Three-digit numbers that can b

  Divisibility rules in math are a set of specific rules that apply to a number to check whether the given number is divisible by a particular number or not. Some known divisibility tests are for numbers 2 to 20. It helps us to find the factors and multiples of numbers without performing long division. A person can mentally check whether a number is divisible by another number or not by applying divisibility rules. Let us learn more about divisibility tests in this article.   Divisible by 2: A number which is even or a number whose last digit is an even number i.e. 0, 2, 4, 6, and 8.   Divisible by 3: The sum of all the digits of the number should be divisible by 3.   Divisible by 4: Number formed by the last two digits of the number should be divisible by 4 or should be 00.   Divisible by 5: Numbers having 0 or 5 as their ones place digit.   Divisible by 6: A number that is divisible by both 2 and 3. A number which is even or a number whose last digit is an even number i.e. 0,

  Find the total number of factors of 15120 50 60 70 80 Ans:  80   The greatest among the numbers 3√2, 3√7, 6√5, 2√20 is 6√5 3√7 2√20 None of these Ans:  6√5     A 4-digit number is formed by repeating a 2-digit number such as 2525, 3232, etc., Any number of this form is always exactly divisible by   Smallest 3-digit prime number 7 11 13 Ans:  Smallest 3-digit prime number     Find the no. of prime factors in the product of 25^12 × 10^7 x 14^7 50 68 54 52 Ans: 52 25^12× 10^7 x 14^7  =(5*5)^12 × (2*5)^7 ×(2*7)^7  =5^12 × 5^12 × 2^7 × 5^7 × 2^7 × 7^7  =5^31 × 2^14 × 7^7  Now add the power to find the number of prime factors  31+14+7 =52 is option D.     How many of the following numbers are divisible by 3 but not by 9.  4320, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276 5 6 7 None of these Ans: 5   A 3-digit number 4p3 is added to another 3-digit number 984 to give the four-digit number 13q7, which is divisible by 11. Then, (p + q) is : 10 11 12 15 Ans: 10 (1+q)-(3+7)=0  q=