Amazon Aptitude Questions with Solutions
Amazon Aptitude Questions with Solutions
1: The difference between 4/17 of 17/19 of a number and 3/38 of the same number is 17.5. Find the number.
a)17. 5 b) 18.5
c) 20 d) 133
Answer: (d)
Explanation:
Let the number be X.
Then, 4/17 of 17/19 of the number is (4/17) * (17/19) * X = (4/19) * X
3/38 of the number= (3/38) * X
Given: the difference between these two values is 17.5.
Hence, [(4/19) * X - (3/38) * X ]= 17.5
Solving the equation, we have X=133
Therefore, the number is 133.
2: a, b, c, and d are four numbers in arithmetic progression. Mean of these four numbers is 20. The common difference between the numbers is 6. Find the product of first and the last numbers.
a) 13
b) 34
c) 319
d) 124
Answer: (c)
Explanation:
Let the four numbers be a, a+b, a+2b, and a+3b
Mean of the four numbers = (a+a+b+a+2b+a+3b)/4 = (4a+6b)/4 = 20
Substituting b as 6, we get the value of a= 11
The product of the first and the last number is 11× 29 which is equal to 319.
3: Find the correct group of signs for the equation to be in order.
48_6_9_17
a) /, +, =
b) +, /, =
c) =, +, /
d) +, =, /
Answer: (a)
Explanation:
One can solve these type of problems using trial and error method.
48 divided by 6 gives 8. 8 added to 9 gives 17.
4: Today is Sunday. I will be attending an interview 4 days after the day before yesterday. On which day will I be attending the interview?
a) Tuesday
b) Wednesday
c) Monday
d) Thursday
Answer: (a)
Explanation:
If today is Sunday, Four days after Sunday will be Thursday, the day before yesterday is Tuesday.
5. If in a certain language, NOIDA is coded as OPJEB, how is DELHI coded in that language?
a.CDKGH
b.EFMIJ
c.FGNJK
d.IHLED
Answer: b
Explanation:
Each letter in the word NOIDA is moved one step forward to form the code OPJEB. So, in DELHI, D will be coded as E, E as F, L as M, H as I, I as J. Thus, the code becomes EFMIJ.
6. If HOT is coded as GNS, How is COLD coded?
a.BNKC
b.DPME
c.EQNF
d.FROG
Answer: a
Explanation:
Each letter in the word HOT is moved one step backward to form the code GNS. So, following the same rule, C will be coded as B, O as N, L as K, and D as C. Thus, the code becomes BNKC.
.
7. Three 6 faced dice are thrown together. The probability that all the three show the same number on them is -.
a. 1/216 b. 1/36 c. 5/9 d. 5/12
Answer: Option b
Explanation:
It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555 and 666. Those are six in number. Further the three dice can fall in 6 * 6 * 6 = 216 ways.
Hence the probability is 6/216 = 1/36
8.Three 6 faced dice are thrown together. The probability that no two dice show the same number on them is -.
a. 7/12
b. 5/9
c. 1/36
d. 5/12
Answer: Option b
Explanation:
No two dice show same number would mean all the three faces should show different numbers. The first can fall in any one of the six ways. The second die can show a different number in five ways. The third should show a number that is different from the first and second. This can happen in 3ways ways.
Thus 6 * 5 * 4 = 120 favourable cases.
The total cases are 6 * 6 * 6 = 216.
The probability = 120/216 = 5/9.
9. A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective.
a. 62/63
b. 125/126
c. 1/63
d. 1/126
Answer: Option d
Explanation:
Out of nine, five are good and four are defective. Required probability = 4C4/9C4 = 1/126
10. A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
a. 17/91
b. 33/91
c. 51/91
d. 65/91
Answer: Option b
Explanation:
Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = 12C4/15C4 = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) = 33/91
11. In a certain code 'LION' is written as LMGJ. How is 'MILK' written in that code?
a.JKFL
b.IJGK
c.KLIM
d.KILM
Answer: b
Explanation:
The order of the words is reversed, and then each letter is moved two steps backward. The reverse of MILK is KLIM. On moving letters two steps backward, K becomes I; L becomes J; I becomes G and M becomes K.
12. If the letters of the word 'BUILDING' are arranged alphabetically, which letter would be farthest from the first letter of the word?
a.D
b.U
c.I
d.N
Answer: b
Explanation:
U is the farthest letter from the first letter of the word. It is the 21st letter of the English alphabets; remaining words of the word come before U in the English alphabets.
13. If TUNE is coded as UUOE, LORD is coded as MOSE, how is FLAME written in this code?
a.GMANE
b.FLBMF
c.GMANF
d.None of these
Answer: a
Explanation:
Each consonant in the word is moved one step forward to code the word. The vowels remain unchanged. The letters F, L, and M are moved one step forward, and vowels A and E remain unchanged. So, FLAME is written as GMANE in this code.
14. If POLICE is coded as 60 in a certain code, what is the code for 'Army'?
a.65
b.70
c.55
d.57
Answer: d
Explanation:
The code is derived by adding the alphabetical positions of the letters of the given word in English Alphabets. So, the code for Army is 57, as the sum of positions of A, R, M and Y is 1+18+13+25 = 57
15. Out of 15 consecutive numbers, 2 are chosen at random. The probability that they are both odds or both primes is -.
a. 10/17
b. 10/19
c. 46/105
d. Cannot be determined
Answer: Option d
Explanation:
There is no definite formula for finding prime numbers among 15 consecutive numbers. Hence the probability cannot be determined.
16. 10 books are placed at random in a shelf. The probability that a pair of books will always be together is -.
a. 1/10
b. 9/10
c. 1/5
d. 3/10
Answer: Option C
Explanation:
10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!
Required probability = 1/5
17. The probability of a lottery ticket being a prized ticket is 0.2. When 4 tickets are purchased, the probability of winning a prize on atleast one ticket is -.
a. 0.4869
b. 0.5904
c. 0.6234
d. 0.5834
Answer: Option b
Explanation:
P(winning prize atleast on one ticket)
= 1 - P("Losing on all tickets")
= 1 - (0.8)^4 = (1 + (0.8)^2)(1 - (0.8)^2)
= (1.64)(0.36) = 0.5904
18: Arrange the following phrases into a complete sentence.
A) of desks, and kids are working
B) on countless group assignments.
C) Nowadays, a typical classroom has pods
a) ABC
b) CAB
c) BCA
d) BAC
Answer: (b)
Explanation:
b) The complete sentence would look like this: Nowadays, a typical classroom has pods of desks, and kids are working on countless group assignments.
By looking at the set of sentences, one can understand that 'Nowadays' has to be the beginning of the sentence. From then on, it is simply putting the phrases together to form a coherent sentence.
19.A function f(x) is defined as f(x) = f(x - 2) - x(x + 2) for all the integer values of x and f(1) + f(4) = 0. What is the value of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)?
a) 0
b) 89
c) -89
d) None of these
Answer: Option C
Let S = f(1) + f(2) + f(3) + f(4) + f(5) + f(6)
As f(1) + f(4) = 0, therefore S = f(2) + f(3) + f(5) + f(6) ------ (1)
f(2) = f(0) - 8
f(3) = f(1) - 15
f(4) = f(2) - 24 = f(0) - 32
f(5) = f(3) - 35 = f(1) - 50
f(6) = f(4) - 48 = f(0) - 80
Put the above values in equation (1), we get
S = f(0) - 8 + f(1) - 15 + f(1) - 50 + f(0) - 80
S = 2(f(0) + f(1)) - 153 ------ (2)
As we already know f(1) + f(4) = 0 ⇒f(1) + f(0) - 32 = 0 ⇒f(1) + f(0) = 32
Putting this value in equation 2, we get S = 2(32) - 153 = -89
So, Ans is option C.
20. In ΔABC, the internal bisectors of ∠ABC and ∠ACB met at I and ∠BAC = 50°. The measure of ∠BIC is
a) 105°
b) 115°
c) 125°
d) 130°
Answer: Option B
I is the In-centre
So, ∠BIC = 90° + 1/2 ∠BAC
= 90° + 1/2 × 50 = 115°
21.The difference between [3/5] of [2/3] a number and [2/5] of[1/4] of the same number is 288. What is the number?
a) 960
b) 850
c) 895
d) 955
Answer: Option A
Let the no. Be [3/5] * [{2/3}x] - [2/5] *[1/4]x = 288
Solving it we will get X=960
22.A, B, C and D are four consecutive odd numbers and their average is 42. What is the product of B and D?
a) 1860
b) 1890
c) 1845
d) 1677
e) None of these
Answer: Option C
As diff. Is same so average should lie between B and C so B is 41 & C is 43 so D must be 45 as we have to find the product of B and D so it would be 1845
23. The cost price of item B is Rs. 150/- more than the cost price of A , Item A was sold at a profit of 10% and Item B was sold at a loss of 20%. If the respective ratio of selling price of items A and B is 11:12, what is the cost price of item B?
a) Rs.450/-
b) Rs.420/-
c) Rs.400/-
d) Rs.350/-
Answer: Option A
The cost price of item B is Rs. 150/- more than the Let us assume cost price of A= X
So that Cost price of B= X+150.
SP of A= X*1.1
SP of B=(X+150)*0.8
Given that
SP of A: SP of B
11:12
So that 1.1X / (X+150)*0.8= 11/12
X=300
CP of B= 300+150=450
Answer is 450.
24. A sum of Rs 731 is divided among A, B and C such that 'A' receive 25% more than 'B' and 'B' receive 25% less than 'C'. What is C's share in the amount?
a) Rs. 172
b) Rs. 200
c) Rs. 262
d) None of these
Answer: Option d
A + B + C = 731 ..... (i)
A = 1.25B, gives A = 1.25 * 0.75 C = 0.9375 C....(ii)
B = 0.75C....(iii)
Using (ii) and (iii) in (i) we get
0.9375C + 0.75C + C = 731, gives C = 272.
So option d is the answer.
25. In how many different ways can letters of the word "PRAISE" be arranged?
a) 720
b) 610
c) 360
d) 210
Answer: Option A
As total number of alphabets in PRAISE are 6, so total no. of ways is 6!=720 So option A is the answer
26. If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 300%, the resultant fraction is [5/18]. What is original fraction?
a) 4/9
b) 4/5
c) 8/9
d) 8/11
Answer: Option A
Let the fraction be [n/d] & after that it becomes [2.5n/4d]=5/18 . So we get the result as [4/9]
27. A car covers the first 30 km of its journey in 45 minutes and the remaining 25 km in 30 minutes. What is the average speed of the car?
a) 60
b) 64
c) 49
d) None of these
Answer: Option d
Total distance/Total time =
= = kmph
= kmph
= (30+25)/[(3/4)+(1/2)]
Average Speed=44kmph
28. Four examiners can examine a certain number of answer papers in 10 days by working for 5 hours a day. For how many hours a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?
a) 8
b) 7.5
c) 10
d) 8.5
Answer: Option C
Examiners Days Hours/Day Papers
4 10 5 x
2 20 ? 2x
So, we required number of hours = so optionC is the answer
Using chain rule,
(4×10×5)/X= (2×20×Y)/2X
X=10 hrs/day
29. A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly?
a) 12
b) 16
c) 18
d) 24
Answer: b
Solution:
Suppose the boy got x sums right and 2x sums wrong. Then, x + 2x = 48 3x = 48 x = 16.
30. A man fixed an appointment to meet the manager, Manager asked him to come two days after the day before the day after tomorrow. Today is Friday. When will the manager expect him?
a) Friday
b) Monday
c) Tuesday
d) Sunday
Answer: b
Solution:
Don’t confuse it with Tuesday.the correct answer is Monday
31.There is a merry-go-round race going on.One person says,”1/3 of those in front of me and 3/4 of those behind me, give the total number of children in the race”. Then the number of children took part in the race?
a) 12
b) 11
c) 13
d) 14
Answer: 3
Solution:
Assume there are x participants in the race. In a round race, number of participants in front of a person wil be x-1 and that behind him wil be x-1. i.e, 1/3(x-1) + 3/4(x-1) = x solving x = 13
32. Find the value of X,Y and Z in the following
X X X X
Y Y Y Y
Z Z Z Z
…………….
Y X X X Z
a) X=9 , Y=2; Z=8
b) X=9 , Y=1; Z=9
c) X=8 , Y=1; Z=8
d) X=9 , Y=1; Z=8
Answer: d
33. The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is?
a) 1008
b) 1015
c) 1022
d) 1032
Answer: b
Solution:
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7 = 1008 + 7 = 1015
34. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is?
a) 12
b) 16
c) 24
d) 48
Answer: d
Solution:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4. So, the numbers 12 and 16. L.C.M. of 12 and 16 = 48.
35.. 252 can be expressed as a product of primes as?
a) 2 x 2 x 3 x 3 x 7
b) 2 x 2 x 2 x 3 x 7
c) 3 x 3 x 3 x 3 x 7
d) 2 x 3 x 3 x 3 x 7
Answer: a
Solution:
Clearly, 252 = 2 x 2 x 3 x 3 x 7.
36. 21, 9, 21, 11, 21, 13, 21, …….
a) 14
b) 15
c) 21
d) 23
Answer: b
Solution:
In this alternating repetition series, the random number 21 is interpolated every other number into an otherwise simple addition series that increases by 2, beginning with the number 9.
37. Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is ?
a) 2 : 3
b) 4 : 3
c) 6 : 7
d) 9 : 16
Answer: b
Solution:
Let us name the trains as A and B. Then, (A’s speed) : (B’s speed) = root b : root a = root 16 : root 9 = 4 : 3.
38. If a and b are positive integers and (a-b)/3.5 = 4/7, then
a) b < a
b) b > a
c) b = a
d) b >= a
Answer: a
39. If 5 women or 8 girls can do a work in 84 days. In how many days can 10 women and 5 girls can do the same work?
a) 31 days
b) 30 days
c) 33 days
d) 32 days
Answer: d
Solution:
Given that 5 women is equal to 8 girls to complete a work so, 10 women=16 girls.
Therefore 10women +5girls=16girls+5girls =21girls.
8 girls can do a work in 84 days then 21 girls= (8*84/21)=32days.
Therefore 10 women and 5 girls can work in 32days
40. If 9 men working 6 hours a day can do a work in 88 days. Then 6 men working 8 hours a day can do it in how many days?
a) 89
b) 99
c) 86
d) 76
Answer: b
Solution:
(M1*D1*T1/W1)=(M2*D2*T2/W2) so (9*6*88/1)=(6*8*d/1) on solving, d= 99days.
41. Walking at ¾ of his usual speed a man is late by 2 ½ hr. the usual time is ?
a) 7
b) 7 ½
c) 8 ½
d) 8
Answer: b
Solution:
Usual speed = S Usual time = T Distance = D New Speed is ¾ S New time is 4/3 T 4/3 T – T = 5/2 T=15/2 = 7 ½
42. In a boat, 25 persons were sitting. Their average weight increased one kilogram when One man goes and a new man comes in. The weight of the new man is 70kgs. Find the Weight of the man who is going?
a) 45
b) 25
c) 36
d) 73
Answer: a
Solution:
Weight increased per person is 1 kg. Total increase in weight = 25 kgs Weight of new man is 70 kgs, (Which means his weight is 25 kgs heavier) The weight of the old man was 70 – 25 = 45 kgs
43. A man can row 4.5 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current?
a) 3.5 km/hr
b) 2.5 km/hr.
c) 4.5 km/hr.
d) 1.5 km/hr
Answer: d
Solution:
Speed of boat in still water (b) = 4.5 km/hr. Speed of boat with stream (Down Stream), D = b + u Speed of boat against stream (Up stream), U = b – u It is given upstream time is twice to that of downstream.
Downstream speed is twiceto that of upstream. So b + u = 2(b – u) u =b/3 = 1.5 km/hr.
44. A sum of money amounts to Rs. 9800 after 5 years and Rs. 12005 after 8 years at the same rate of simple interest. The rate of interest per annum is?
a) 5%
b) 8%
c) 12%
d) 18%
Answer: c
Solution:
S.I. for 3 years = Rs. (12005 – 9800) = Rs. 2205. S.I. for 5 years = Rs. (2205/3) x 5 = Rs. 3675 Principal = Rs. (9800 – 3675) = Rs. 6125. Hence, rate = (100 x 3675)/( 6125 x 5) % = 12%
45. A man starts walking at 3 pm. he walks at a speed of 4 km/hr on level ground and at a speed of 3 km/hr on uphill, 6 km/hr downhill and then 4 km/hr on level ground to reach home at 9 pm. What is the distance covered on one way?
a) 12 km
b) 23 km
c) 45 km
d) 65 km
Answer: a
Solution:
lets us consider t1 = time taken on level road. t2 = uphill. t3 = down hill; the distance traveled uphill and down hill same so t2*3 = 6*t3; => t2 = 2t3;—> (1) total time = 2*t1 + t2 + t3 = 6 hours —> (2) 2t1+3t3 = 6 –>(3) total distance= 2*(4t1) + 3*t2+ 6*t3 —> (4) substitute (1) in (4) 8t1 + 12t3 => 4(2t1+3t3) then from (3) the total distance will become 4*6= 24 => one way distance = 12km
46. In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is
a) 5
b) 7
c) 10
d) 12
Answer: b
Solution:
Let the number of cows be x and the number of hens be y. Then, 4x + 2y = 2 (x + y) + 14 4x + 2y = 2x + 2y + 14 2x = 14 x = 7.
47. I have a few sweets to be distributed. If I keep 2, 3 or 4 in a pack, I am left with one sweet. If I keep 5 in a pack, I am left with none. What is the minimum number of sweets I have to pack and distribute?
a) 25
b) 37
c) 54
d) 65
Answer: a
Solution:
Clearly, the required number would be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5.
48. 2 trains starting at the same time from 2 stations 200km apart and going in opposite direction cross each other at a distance of 110km from one of the stations.what is the ratio of their speeds?
a) 11:9
b) 11:8
c) 10:9
d) 10:90
Answer: a
Solution:
In same time ,they cover 110km & 90 km respectively so ratio of their speed =110:90 = 11:9
49. If 9x-3y=12 and 3x-5y=7 then 6x-2y = ?
a) -5
b) 4
c) 2
d) 8
Answer: d
Solution:
Consider 9x – 3y = 12………divide both sides by 3: 3x – y = 4…………now multiply both sides by 2: 6x – 2y = 8 So, it`s (d)
50. Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
a) Rs. 4, Rs. 23
b) Rs. 13, Rs. 17
c) Rs. 15, Rs. 14
d) Rs. 17, Rs. 13
Answer: b
Solution:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A. Then, 2x + 3y = 77 …(i) and 3x + 2y = 73 …(ii) Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17. Putting y = 17 in (i), we get: x = 13.
51. The total of the ages of Amar, Akbar, and Anthony is 80 years. What was the total of their ages three years ago?
a) 71 years
b) 72 years
c) 74 years
d) 77 years
Answer: a
Solution:
Required sum = (80 – 3 x 3) years = (80 – 9) years = 71 years.
52. A man took a loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was ?
a) Rs. 2000
b) Rs. 10,000
c) Rs. 15,000
d) Rs. 20,000
Answer: c
Solution:
Principal = Rs. (100 x 5400)/(12*3) = Rs. 15000.
53. The total age of A & B is 12 years more than the total age of B & C. C is how many years younger than A?
a) C is 12 years younger than A
b) C is 11 years younger than A
c) C is 18 years younger than A
d) C is 22 years younger than A
Answer: a
Solution:
From the given data A+B = 12+(B+C) A+B-(B+C) = 12 A-C=12 years. C is 12 years younger than A
54. The present age of a father is 3 years more than three times the age of his son.Three years hence, father as age will be 10 years more than twice the age of the son.Find the present age of the father. ?
a) 23 years
b) 30 years
c) 33 years
d) 42 years
Answer: c
Solution:
Let the present age be ‘x’ years. Then father’s present age is 3x+3 years. Three years hence (3x+3)+3=2(x+3)+10 x=10 Hence father’s present age = 3x+3 =[ (3 x 10) + 3] = 33 years.
55. In one hour a boat goes 11 km along the stream and 5 km against the stream.The speed of the boat in still water is?
a) 8 kmph
b) 7 kmph
c) 8.5 kmph
d) 9 kmph
Answer: a
Solution:
Speed in still water A = ½ ( 11+5) km/hr A= 8 kmph
56, A train 110 m long travels at 60 kmph. How long does it take to pass a telegraph post by the side of the track?
a) 5.6 seconds
b) 6.5 seconds
c) 6.6 seconds
d) 6.7 seconds
Answer: c
Solution:
Speed of train = 60 ×5/18 m/s = 50/3 m/s ? Time taken to cross the telegraph post = 110/(50/3) = 6.6 seconds
57. The average ages of three persons is 27 years. Their ages are in the proportion of 1:3:5. What is the age in years of the youngest one among them?
a) 8
b) 6
c) 7
d) 9
Answer: d
Solution:
Let the age of three persons be x, 3x and 5x => 9x/3 = 27 = > x = 9
58. The greatest number of four digits which is divisible by 15, 25, 40 and 75 is?
a) 9000
b) 9400
c) 9600
d) 9800
Answer: c
Solution:
The greatest number of 4-digits is 9999. L.C.M. of 15, 25, 40 and 75 is 600. On dividing 9999 by 600, the remainder is 399. Required number (9999 – 399) = 9600.
59.Pointing to a photograph a lady tell’s Pramod,”I am the only daughter of this lady and her son is your maternal uncle,”How are the speakers related to Pramod’s father?
a) Sister-in-law
b) Wife
c) Either (A) or (B)
d) Neither (A) Nor (B)
Answer: Option b
Solution:
Clearly the speakers brother is Pramod’s maternal uncle .So the speaker is Pramod’s mother or his father wife.
60. 1. Andhra Pradesh 2. Universe 3.Tirupathi 4.World 5. India
a) 1,5,3,2,4
b) 2,1,3,5,4
c) 3,1,5,4,2
d) 5,4,2,1,3
Answer: Option c
48. Examine the following statements:
a. Lady finger is tastier than cabbage
b. Cauliflower is tastier than lady’s finger
c. Cabbage is not tastier than peas
The conclusion that can be drawn from these statements is that
a) Peas are as tasty as lady finger
b) Peas are as tasty as cauliflower and lady finger
c) Cabbage is the least tasty of the four vegetables
d) Cauliflower is tastier than cabbage
Answer: Option c
Solution:
According to the given information in the question
Lady Finger > Cabbage Cauliflower> Lady Finger Cabbage<= Peas
From equations (i) and (ii) Cauliflower> Lady’s Finger> Cabbage
Thus, Cabbage is the least tasty of the four vegetables.
61. Statement:
The employees association has appealed to the Managers of Company ‘S’ to introduce written examination for Clerical cadre recruitment to prevent selection of incompetent persons.
Assumptions:
I. So far the company ‘S’ used to select candidates with out conducting a written examination.
II. A written examination can help to identify competent persons.
III. At higher level written examination may not be of much use.
a) Only I and II
b) Only II and III
c) Only II
d) Only I and III
e) None of these
Answer: Option a
Solution:
To appeal to start the written examination clearly hints about assumption I. Employees association assumes II that is why they have appealed so.
62. If you’re a fitness walker, there is no need for a commute to a health club. Your neighborhood can be your health club. You don’t need a lot of fancy equipment to get a good workout either. All you need is a well-designed pair of athletic shoes.
This paragraph best supports the statement that
a) fitness walking is a better form of exercise than weight lifting.
b) a membership in a health club is a poor investment.
c) walking outdoors provides a better workout than walking indoors.
d) fitness walking is a convenient and valuable form of exercise.
e) poorly designed athletic shoes can cause major foot injuries.
Answer: Option d
Solution:
By stating that fitness walking does not require a commute to a health club, the author stresses the convenience of this form of exercise. The paragraph also states that fitness walking will result in a good workout. Choice a is incorrect because no comparison to weight lifting is made. Choice b may seem like a logical answer, but the paragraph only refers to people who are fitness walkers, so for others, a health club might be a good investment. Choice c is not in the passage. Although choice e seems logical, the paragraph does not indicate that the wrong shoes will produce major injuries.
63. If shaloo is taller than Rakhi but shorter than preran and Rakhi is as tall as Meghana but taller than Komal then Meghana is?
a) Shorter than Rakhi
b) Shorter than Komal
c) as tall as shaloo
d) Taller than Preran
e) Shorter than Shaloo
Answer: Option e
Solution:
As given we have Prerna>Shaloo>Rakhi>:
Rakhi= Meghna, Rakhi>komal
These the sequence of height becomes
Prerna>shaloo>Rakhi= Meghna>Komal
Clearly, Meghana is shorter than shaloo.
64. Assertion:
The problem-solving ability, mental performance and memory of the employees of company C are deteriorating.
RI. Due to tight schedule at company C, the employees of the company are skipping their breakfast regularly.
RII. The job is physical in nature, but not mental.
a) Only RI and not RII is the reason for the assertion.
b) only RII and not RI is the reason for the assertion.
c) either RI or RII, but not both, is the reason for the assertion.
d) neither RI nor RII is the reason for the assertion.
e) both RI and RII are the reason for the assertion.
Answer: Option d
65. The workers from asbestos industries do not protest against the health hazards and lack of medical facilities as most of them do not suffer from asbestos dust?
a) If the inference is definitely true
b) If the inference is probably true
c) If the data are inadequate
d) If the inference is probably false
e) If the inference is definitely false
Answer: Option e
Solution:
From the clause afraid to protest for fear of losing job the given reason can be nullified.
66. A lotus flower always has
a) Petals
b) Mud
c) Root
d) Water
Answer: Option a
67. In which of the following years were the total imports made by all the three companies together with the maximum?
a) 1996 only
b) 1997 only
c) 1995 only
d) 1995 and 1997 only
e) None of these
Answer: Option c
Solution:
The total imports made by all the three companies together: From the heights of the points we observe that the total heights of three points is the maximum either in 1995 or 1997. If you observe carefully, our clear answer is 1995, but to be sure we find actual values for the two years.
In 1995 = 70 + 80 + 85 = 235.
In 1997 = 75 + 70 + 85 = 230.
Clearly, 1995 is the desired year.
68. 3 5 35 10 12 35 17 ? ?
a) 22, 35
b) 35, 19
c) 19 ,35
d) 19, 24
e) 22, 24
Answer: Option c
Solution:
This is an alternating addition series, with a random number, 35, interpolated as every third number. The pattern of addition is to add 2, add 5, add 2, and so on. The number 35 comes after each “add 2” step.
69. book
a) fiction
b) pages
c) pictures
d) learning
Answer: Option b
Solution:
The necessary part of a book is its pages; there is no book without pages. Not all books are fiction (choice a), and not all books have pictures (choice c). Learning (choice d) may or may not take place with a book.
70.glacier
a) mountain
b) winter
c) prehistory
d) ice
Answer: Option d
Solution:
A glacier is a large mass of ice and cannot exist without it. A glacier can move down a mountain, but it can also move across a valley or a plain, which rules out choice a. Glaciers exist in all seasons, which rules out choice b. There are many glaciers in the world today, which rules out choice c.
71. Four of the following five are alike in a certain way and so form a group. Which is the one that does not belong to that group?
a) PY8
b) EK5
c) RV3
d) DG2
e) JR6
Answer: Option e
Solution:
In all others, the digit indicates the gap between the two letters.
72. In a coded language LHOSPITALl is written as L32574618l in the same language LPOSTALl would be written as?
a) 752618
b) 725618
c) 725168
d) 725681
Answer: Option b
Amazon English Test Model Papers
In this section, we have provided Amazon English Question and Answers with detailed explanation. Before going to attend for the Amazon Recruitment candidates should refer the provided sample questions to get the best result.
73.15 men take 21 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men?
A. 10
B. 20
C. 30
D. 40
Answer: Option C
Explanation:
3W = 2M
15M ------ 21 * 8 hours
21 W ------ x * 6 hours
14 M ------ x * 6
15 * 21 * 8 = 14 * x * 6
x = 30
74.Some persons can do a piece of work in 12 days. Two times the number of these people will do half of that work in?
A. 3 days
B. 4 days
C. 6 days
D. 12 days
Answer: Option A
Explanation:
12/ (2 * 2) = 3 days
75. Two pipes X and Y can separately fill a cistern in 18 and 24 hours respectively. If they are turned on alternately for one hour each, how long will it take to fill the cistern?
A. 20 hours 30 min
B. 24 hours
C. 18 hours 30 min
D. 16 hours
Answer: Option A
Explanation:
1/18 + 1/24 = 7/72
72/7 = 10 2/7
7/72 * 10 = 35/36 ----- 20 hours
WR = 1 – 35/36 = 1/36
1 h ----- 1/18
? ----- 1/36 = 1/2 hours
=> 20 1/2 hours
76. The fourth proportional to 12, 14 and 18 is?
A. 21
B. 20
C. 22
D. 28/3
Answer: Option A
Explanation:
(14*18)/12 = 21
77. The mean proportional between 4 and 9 is?
A. 9
B. 3
C. 6
D. 4
Answer: Option C
Explanation:
78. The proportion of copper and zinc in the brass is 13:7. How much zinc will there be in 100 kg of brass?
A. 20 kg
B. 35 kg
C. 55 kg
D. 14 kg
Answer: Option B
Explanation:
7/20 * 100 = 35
79.The ratio of the number of ladies to gents at a party was 1:2 but when 2 ladies and 2 gents left, the ratio became 1:3. How many people were at the party originally?
A. 36
B. 24
C. 12
D. 6
Answer: Option C
Explanation:
x, 2x
(x-2):(2x-2) = 1:3
3x-6 = 2x-2
x = 4
x+2x = 3x
=> 3*4 = 12
80. The first three terms of a proportion are 3, 9 and 12. The fourth term is?
A. 4
B. 6
C. 18
D. 36
Answer: Option D
Explanation:
(9*12)/3 = 36
81. A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?
A. 10cm
B. 20cm
C. 25cm
D. 30cm
Answer: Option B
Explanation:
1: 2/5 = 5: 2
2/7 * 70 = 20
82.1000 men have provisions for 15 days. If 200 more men join them, for how many days will the provisions last now?
A. 10.5
B. 11.5
C. 12.5
D. 10.4
Answer: Option C
Explanation:
1000*15 = 1200*x
x = 12.5
83. A garrison of 400 men had a provision for 31 days. After 28 days 280 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?
A. 3 days
B. 8 days
C. 10 days
D. 6 days
Answer: Option C
Explanation:
400 --- 31
400 --- 3
120 --- ?
400*3 = 120*x => x =10 days
84. An amount of money is to be divided between P, Q and R in the ratio of 3:7:12. If the difference between the shares of P and Q is Rs.2400, what will be the difference between Q and R's share?
A. Rs.2800
B. Rs.3000
C. Rs.2400
D. Rs.3200
Answer: Option B
Explanation:
4 --- 2000
5 --- ? => 3000
85.A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 75, the runs scored by B are?
A. 15
B. 18
C. 21
D. 24
Answer: Option B
Explanation:
A:B = 2:3
B:C = 2:5
A:B:C = 4:6:15
6/25 * 75 = 18
86. A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 27, what is the total amount?
A. Rs.90
B. Rs.105
C. Rs.96
D. Rs.120
Answer: Option B
Explanation:
x:y:z = 100:45:30
20:9:6
9 --- 27
35 --- ? => 105
87 .Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
A. 100
B. 115
C. 120
D. 110
Answer: Option C
Explanation:
4x 5x 6x
100 50 25
400x + 250x + 150x = 16000
x = 20
6x = 120
88. Sushil got thrice as many marks in English as in Science. His total marks in English, Science and Maths are 162. If the ratio of his marks in English and Maths is 3:5, find his marks in Science?
A. 18
B. 24
C. 30
D. 28
Answer: Option A
Explanation:
S:E = 1:3
E:M = 3:5
------------
S:E:M = 3:9:15
3/27 * 162 = 18
89. Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is?
A. 3:8
B. 9:31
C. 8:21
D. 10:27
Answer: Option B
Explanation:
1/4 : 3/4 = (1:3)5 = 5:15
1/5 : 4/5 = (1:4)4 = 4:16
------
9:31
90. If A:B = 1/2: 1/3 B:C = 1/2:1/3 then A:B:C?
A. 2:3:3
B. 1:2:6
C. 1/6:1/2:1/3
D. 9:6:4
Answer: Option D
Explanation:
A:B = 1/2:1/3 = 3:2
B:C = 1/2:1/3 = 3:2
--------------------
A:B:C = 9:6:4
91. Divide Rs. 1500 among A, B and C so that A receives 1/3 as much as B and C together and B receives 2/3 as A and C together. A's share is?
A. Rs.600
B. Rs.525
C. Rs.375
D. Rs.0
Answer: Option C
Explanation:
A+B+C = 1500
A = 1/3(B+C); B = 2/3(A+C)
A/(B+C) = 1/3
A = 1/4 * 1500 => 375
92. Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
A. Rs.260
B. Rs.270
C. Rs.360
D. Rs.540
Answer: Option D
Explanation:
A+B+C = 1170
4A = 3B = 2C = x
A:B:C = 1/4:1/3:1/2 = 3:4:6
6/13 * 1170 = Rs.540
93. She is not interested in —– sweets?
a) eat
b) eaten
c) eating
d) to be eating
Answer: Option c
94. Competition
a) compete
b) complete
c) competent
d) competence
Answer: Option a
95. A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?
A. Rs.50
B. Rs.75
C. Rs.100
D. Rs.150
Answer: Option A
Explanation:
A+B+C = 500
A+C = 200
B+C = 350
--------------
A+B+2C = 550
A+B+C = 500
----------------
C = 50
96. There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 580. The number of hares in the zoo is?
A. 110
B. 100
C. 90
D. 85
Answer: Option C
Explanation:
200*2 = 400
580
-----
180
1----2
?----180 = 90
97. The compound ratio of 5:6, 3:2 and 4:5?
A. 12:13
B. 1:4
C. 1:5
D. 1:1
Answer: Option D
Explanation:
5/6 * 3/2 * 4/5 = 1/1
1:1
98. Many teachers believe that the easiest way of maintaining order and discipline in classrooms is by instilling fear in the minds of the students. —– Parents too are to blame for this syndrome for they make life difficult for their children by setting unrealistic goals?
(A) Its a pity that often lack in self-confidence.
(B) No wonder they often lack in self-confidence.
(C) It is practically impossible for the teachers to attend to each student’s problems.
a) A and B
b) A and C
c) Only A
d) All the three
e) None of these
Answer: Option a
Solution:
Only statements A and B can Join the two sentences. C is different from them.
99. Two numbers are in the ratio 3:5. If 9 be subtracted from each, they are in the ratio of 9:17. The first number is:
A. 36
B. 27
C. 18
D. 30
Answer: Option A
Explanation:
(3x-9):(5x-9) = 9:17
x = 12 => 3x = 36
100. The exhibition committee
(P) attractive and useful
(Q) to make the exhibition
(R) making efforts
(S) has been
a) SRQP
b) QPRS
c) SRPQ
d) QPSR
Answer: Option b
101. In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?
A. 42 liters
B. 56 liters
C. 60 liters
D. 77 liters
Answer: Option C
Explanation:
2:1 --- 60
1:2
2:4
---------------
3
3 ----------- 60
3 ----------- ? ( 60 liters)
102. 1600 men have provisions for 28 days in the temple. If after 4 days, 400 men leave the temple, how long will the food last now?
A. 28 days
B. 30 days
C. 32 days
D. 35 days
Answer: Option C
Explanation:
1600 ---- 28 days
1600 ---- 24
1200 ---- ?
1600*24 = 1200*x
x = 32 days
103.There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 19 days more?
A. 60 men
B. 40 men
C. 25 men
D. 20 men
Answer: Option B
Explanation:
760 ---- 22
760 ---- 20
x ----- 19
x*19 = 760*20
x = 800
(--) 760
-------
40
104. Rs. 1300 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/2:1/3:1/4?
A. Rs.100
B. Rs.200
C. Rs.300
D. Rs.600
Answer: Option C
Explanation:
1/2:1/3:1/4 = 6:4:3
3/13*1300 = 300
105. A gets 3 times as much money as B gets, B gets only Rs.25 more then what C gets. The three gets Rs.675 in all. Find the share of B?
A. Rs.125
B. Rs.115
C. Rs.110
D. Rs.140
Answer: Option D
Explanation:
A+B+C = 675
A = 3B
3B+B+B-25 = 675
5B = 700
B = 140
106. Rs.590 is divided amongst A, B, C so that 5 times A's share, six times B's share and eight times C's share are all equal. Find C's share?
A. Rs.130
B. Rs.150
C. Rs.170
D. Rs.175
Answer: Option B
Explanation:
A+B+C = 590
5A = 6B = 8C = x
A:B:C = 1/5:1/6:1/8
= 24:20:15
15/59 * 590 = Rs.150
107. Many teachers believe that the easiest way of maintaining order and discipline in classrooms is by instilling fear in the minds of the students. —– Parents too are to blame for this syndrome for they make life difficult for their children by setting unrealistic goals.
(A) Its a pity that often lack in self-confidence.
(B) No wonder they often lack in self-confidence.
(C) It is practically impossible for the teachers to attend to each student’s problems.
a) A and B
b) A and C
c) Only A
d) All the three
e) None of these
Answer: Option a
Solution:
Only statements A and B can Join the two sentences. C is different from them.
108. A' and 'B' complete a work togather in 8 days.If 'A' alone can do it in 12 days.Then how many day 'B' will take to complete the work?
a) 25 days
b) 24 days
c) 20 days
d) None of these
Answer: 24 days
Explanation:
A & B one day work = 1/8
A alone one day work = 1/12
B alone one day work = (1/8 - 1/12) = ( 3/24 - 2/24)
=> B one day work = 1/24
so B can complete the work in 24 days.
109. If A alone can do a piece of work in 8 days and B alone can do the same work in 12 days. How many days A and B required to finish the same work if they work togather?
a) 24/5 days
b) 24 days
c) 5day days
d) 5/24 days
e) None of these
Answer: 24/5 days
Explanation:
A alone one day work = 1/8
B alone one day work = 1/12
Both A and B one day work = (1/8 + 1/12) = (3/24 + 2/24)
= 5/24
so A and B together finish the work in 24/5 day
or 4 4/5 days.
110. When a number is divided by 13, the remainder is 11. When the same number is divided by 17, then remainder is 9. What is the number ?
a) 339
b) 349
c) 369
d) Data inadequate
Answer: 349
Explanation:
x = 13p + 11 and x = 17q + 9
111. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
a) 120 metres
b) 180 metres
c) 324 metres
d) 150 metres
Answer: 150 metres
Explanation:
Length of the train = (Speed x Time) =50/3 x 9 m = 150 m.
DIRECTIONS: Go through all the options and mark the one which does not belong to the group.
112. 10, 13, 234, 681, 997
a) 681
b) 13
c) 234
d) 10
Answer: Option A
10⇒ 1+0 =1 or 1^2
13⇒ 1+3 = 4 or 2^2
234 ⇒ 2+3+4 = 9 or 3^2
681 ⇒ 6+8+1 = [15]
997 ⇒ 9+9+7 = 25 or 5^2
So the sum of the digits in all the numbers is a perfect square except for 681, hence that is odd.
113. Choose amongst the Options below.
a) Heed
b) Led
c) Heap
d) Head
Answer: Option B
Except in the word Led, in all other words there are two vowels.
Hence the answer is option B.
DIRECTIONS for the question 114 -120: What should come in place of question mark (?) in the following number/alphabetic series
114 . C – 3, E – 5, G – 7, I – 9, ?, ?
a) K – 11, M – 13
b) M – 18, K – 14
c) X – 24, M – 21
d) O – 15, X – 24
Answer: Option A
115. 5, 16, 51, 158, ?
a) 483
b) 481
c) 1454
d) 1452
Answer: Option B
5 × 3 + 1 = 16
16 × 3 + 3 = 51
51 × 3 + 5 = 158
158 × 3 + 7 = [481]
116.9 × 2: 9 × 9 : : 9 × 5 : ?
a) 9 × 6
b) 9 × 7
c) 9 × 8
d) 9 × 4
Answer: Option A
9×2=18
9×9=81
The digits of resultant have interchanged positions therefore,
9×5=45
9×6=54
117. AFI, JOR, MRU, ?
a) HMP
b) PMO
c) RJL
d) GJN
Answer: Option A
118. bc, cde, de, efg, fg, ?
a) fgh
b) hij
c) ijk
d) ghi
Answer: Option D
The answer should be the last alphabhet of fg ( i.e g ) and the next two alphabets i.e hi . Hence answer is ghi
bc → cde → de → efg → fg → ghi
119. A man showed a boy next to him and said – “He is the son of my wife’s sister-in-law, but I am the only child of my parents.” How is man's son related to him?
a) Brother
b) Uncle
c) Nephew
d) Cousin
Answer: Option D
The boy is the son of man’s brother-in-law. Therefore, man’s son is the cousin of that boy.
120. Find the correct group of signs to solve the equation. 24 * 16 * 8 * 32
a) + =
b) x / =
c) + - =
d) / - =
Answer: Option C
The best way to solve this question is by hit and trial . Use the answer options and find the value.
24 * 16 * 8 * 32
⇒ 24 + 16 - 8 = 32
⇒ 40-8 = 32
In this case, option C is correct.
References:
https://cpt.hitbullseye.com/Amazon-Aptitude-Questions.php
https://www.conduiraonline.com/index.php/detail/1726-amazon-aptitude-test-questions
https://www.indiabix.com/placement-papers/amazon/6612
https://www.allindiajobs.in/2014/10/amazon-placement-papers-interview-questions.html
https://cpt.hitbullseye.com/Amazon-Reasoning-Test.php
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